Question

write the discriminant for the following quadratic equation (x-1)(2x-1)=0

Answer 1

Hey

Here is your answer,

(x-1)(2x-1)=0
2x^2 -x -2x+1=0
2x^2 -3x+1=0

To find discriminant:

b^2 - 4ac=0
(3)^2 -4x2x1=0
9-8=0
1=0

since it is not equal to zero and it has positive sign , it has real roots.

Hope it helps you!

Answer 2

Answer:

The value of discriminant is 1

Step-by-step explanation:

Given the quadratic equation

$(x-1)(2x-1)=0$

we have to find the discriminant

$(x-1)(2x-1)=0$

$2x^2 -x -2x+1=0$

$2x^2 -3x+1=0$

Comparing the above equation with standard quadratic equation $ax^2+bx+c=0$

a=2, b=-3, c=1

To find discriminant:

$Discriminant=b^2 - 4ac$

$=(-3)^2 -4(2)(1)$

$=9-8=1$

The value of discriminant is 1