Question

Write the discriminant of the quadratic equation px2 + qx- r = 0

Answer 1

Answer:

Step-by-step explanation:

D=b^-4Ac

Q^ -4×p×r

=Q^+4pr.........

Answer...

Answer 2

Answer:

$x = \frac{-q\pm\sqrt{q^2+4pr}}{2p}$

Step-by-step explanation:

General form of quadratic equation : $ax^{2}+bx+c=0$

Given equation: $px^2 + qx- r = 0$

On comparing with general form

a = p

b = q

c = -r

Formula of discriminant : $x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Substitute the value sin the formula .

$x = \frac{-q\pm\sqrt{q^2-4p(-r)}}{2p}$

$x = \frac{-q\pm\sqrt{q^2+4pr}}{2p}$

Thus the discriminant of given equation is     $x = \frac{-q\pm\sqrt{q^2+4pr}}{2p}$