Math, asked by vaishu03tarun, 10 months ago

write the divisibility rule of 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 with examples​

Answers

Answered by jobchd
11

Answer:

Divisibility Tests for 2, 3, 5, 7 and 11

This shows you the divisibility tests for 2, 3, 5, 7, and 11, so you can tell if those numbers are factors of a given number or not without dividing.

Divisibility Test for 2: The last digit is 0, 2, 4, 6, or 8.

Divisibility Test for 3: The sum of the digits is divisible by 3.

Divisibility Test for 5: The last digit is 0 or 5.

Divisibility Test for 7: Cross off last digit, double it and subtract. Repeat if you want. If new number is divisible by 7, the original number is divisible by 7.

Divisibility Test for 11: For a 3-digit number, sum of the outside digits minus the middle digit must be 0 or 11.

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