Question

Write the edge length & Axial angle of orthorhombic & monoclinic.

Answer 1

Answer:

The relation a = b = c and α = β = γ holds for cubic and rhombohedral systems.Cubic a = b = c α = β = γ = 90o Rhombohedral a = b = c α = β = γ≠ 90o.

Explanation:

In geometry and crystallography, a Bravais lattice, named after Auguste Bravais (1850),[1] is an infinite array of discrete points generated by a set of discrete translation operations described in three dimensional space by:

{\displaystyle \mathbf {R} =n_{1}\mathbf {a} _{1}+n_{2}\mathbf {a} _{2}+n_{3}\mathbf {a} _{3}}

where ni are any integers and ai are primitive vectors which lie in different directions (not necessarily mutually perpendicular) and span the lattice. This discrete set of vectors must be closed under vector addition and subtraction. For any choice of position vector R, the lattice looks exactly the same.

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Answer 2

Answer:

The edge length & Axial angle :

For orthorhombic :- a = b = c  and α = β = γ =90°

For monoclinic:  a≠ b≠ c and α=β=90° and  γ ≠ 90°.

Explanation:

• Orthorhombic is a crystal system in which all three edge length are unequal but the interfacial angle between the faces are equal to 90°.  Therefore, edge length $a=b=c$ and axial angle $\alpha =\beta =\gamma=90^{o}$. Orthorhombic has four bravais lattice.
• Monoclinic is crystal lattice in which all the edge lengths of unit cell are unequal and the two axial angles are equal but the third one is different. Therefore, $a\neq b\neq c$ and $\alpha =\beta =90^{o}$, $\gamma\neq 90^{o}$. It has two bravais lattice.