Write the electrode reactions during
electrolysis of molten KCl.
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20
Answer:
2K+ + 2e- → 2K (potassium metal at the (-)cathode). 2Cl- - 2e- → Cl2 (chlorine gas at the (+)anode). Potassium ions gain electrons (reduction) to form potassium atoms. Chloride ions lose electrons (oxidation) to form chlorine atoms.
Answered by
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2K+ + 2e- → 2K (potassium metal at the (-)cathode). 2Cl- - 2e- → Cl2 (chlorine gas at the (+)anode). Potassium ions gain electrons (reduction) to form potassium atoms. Chloride ions lose electrons (oxidation) to form chlorine atoms.
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