Question

write the electronic configuration of Ce3+ ion and calculate the magnetic moment on the basis of spin and orbital contribution

Answer 1

Answer:

Using Hund's rule to find the electronic configuration of Ce ion,

Ce : 1s² 2s² 2p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶ 4f¹ 5d¹ 6s²

Now, when the cesium atom looses three electrons to form Ce³⁺ ion, it will loose electrons from the 5th d-shell and 6th s-shell, hence,

Ce³⁺ :   1s² 2s² 2p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶ 4f¹ ;

Hence having only one unpaired electron.

Finding the magnetic spin (μ) only on the basis of spin-only formula,

μ = √n(n+2) where n = number of unpaired electrons.

Here n =2 (5s²)

μ = √2(2+2) = √8 = 2√2 = 2.828 BM (bohr magneton unit)

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