Question

write the electronic configuration of the element which belongs of 2nd and 3rd period of preodic table​

Answer 1

Answer:

for 2nd . 2

for 3rd . 2, 1

Explanation:

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Answer 2

Answer:

K, L, M (2,8,2)

Explanation:

As it is in 3rd period, it has 3 shells and since it is in the second group, it contains 2 valence electrons. Thus, the electronic configuration will be 2,8,2. 

Hence, it has 12 electrons, that is, magnesium. 

       2Mg+O2→2MgO.

It satisfies given condition which is a basic oxide.