write the empirical formula and molecular formula having mass percentage carbon 75% and hydrogen 25%
Answers
Answered by
3
C =75 ÷ 12 = 6.4
H = 25 ÷ 1 = 25
C = 6.4÷6.4 = 1
H = 25 ÷ 6.4 = 3.9 = 4
Hence empirical formula is ch4
And molecular farmula can be multiple of it. ..
Like
C2h8
C3h12
C4h16
Etc
Hope it helps you ... if it helps you mark as brainlist plz PlzZ plz PlzZ plz PlzZ plz
H = 25 ÷ 1 = 25
C = 6.4÷6.4 = 1
H = 25 ÷ 6.4 = 3.9 = 4
Hence empirical formula is ch4
And molecular farmula can be multiple of it. ..
Like
C2h8
C3h12
C4h16
Etc
Hope it helps you ... if it helps you mark as brainlist plz PlzZ plz PlzZ plz PlzZ plz
Similar questions