write the equation 4x=6(1-y)+3x in the form ax+by+c and also find the coordinates of the points where its graph cuts the 2 axis
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4x = 6 - 6y + 3x
4x - 6 +6y -3x =0
x+6y - 6 =0
(6,0) in x axis
(0,10 in y axis
4x - 6 +6y -3x =0
x+6y - 6 =0
(6,0) in x axis
(0,10 in y axis
Answered by
0
Step-by-step explanation:
mutiply 6 with (1-y) and take it to L.H.S so we will get the ax+by+c
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