Computer Science, asked by cshekhar60478, 4 months ago

write the equation for a-photosynthesis b- water electrolysis​

Answers

Answered by RamArora
0

Answer:

6CO2 + 6H2O → C6H12O6 + 6O2 + 6H2O.

Explanation:

mark me as brainliest follow karlo

Answered by ayushisingh81
1

Answer:

a. The equation of photosynthesis is: 6CO2 + 6H2O → C6H12O6 + 6O2.

b. The equation of water electrolysis: 2 H2O(l) → 2 H2(g) + O2(g)

Explanation:

a. The equation of photosynthesis is : 6CO2 + 6H2O → C6H12O6 + 6O2. This means that the reactants, six carbon dioxide molecules and six water molecules, are converted by light energy captured by chlorophyll (implied by the arrow) into a sugar molecule and six oxygen molecules, the products.

b. In pure water at the negatively charged cathode, a reduction reaction takes place, with electrons (e−) from the cathode being given to hydrogen cations to form hydrogen gas. The half reaction, balanced with acid, is:

Reduction at cathode: 2 H+(aq) + 2e− → H2(g)

At the positively charged anode, an oxidation reaction occurs, generating oxygen gas and giving electrons to the anode to complete the circuit:

Oxidation at anode: 2 H2O(l) → O2(g) + 4 H+(aq) + 4e−

The same half-reactions can also be balanced with the base as listed below. Not all half-reactions must be balanced with acid or base. Many do, like the oxidation or reduction of water listed here. To add half reactions they must both be balanced with either acid or base. The acid-balanced reactions predominate in acidic (low pH) solutions, while the base-balanced reactions predominate in basic (high pH) solutions.

Cathode (reduction): 2 H2O(l) + 2e− → H2(g) + 2 OH−(aq)

Anode (oxidation): 2 OH−(aq) → 1/2 O2(g) + H2O(l) + 2 e−

Combining either half reaction pair yields the same overall decomposition of water into oxygen and hydrogen:

Overall reaction: 2 H2O(l) → 2 H2(g) + O2(g)

The number of hydrogen molecules produced is thus twice the number of oxygen molecules. Assuming equal temperature and pressure for both gases, the produced hydrogen gas has, therefore, twice the volume of the produced oxygen gas. The number of electrons pushed through the water is twice the number of generated hydrogen molecules and four times the number of generated oxygen molecules.

I hope it helps ☺️

Similar questions