Question

Write the equation for the dissociation of KBr in water.(Write the ions formed)
KBr------->

Answer 1

Answer:

When KBr is dissolved in water, its crystal lattice feels the many, strong attraction forces of water molecules on both K⁺ cations and Br¯ anions.

Such forces eventually overcome the electrostatic attraction among oppositely charged ions that hold the solid, crystalline KBr together.

As it turns out, each ion gets surrounded by a number of differently-orientated water molecules in the so-called solvation sphere. As there are usually 4 to 6 water molecules per ion, the equation can be written like this:

KBr + H₂O → [K(H₂O)₆]⁺ + [Cl(H₂O)₆]¯

Explanation:

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Answer 2

The equation for the dissociation of KBr in water is $\[KBr \to {K^ + } + B{r^ - }\]$.

Explanation:

• When potassium bromide is dissolved in water, it gets dissociated into potassium ions and bromide ions.
• It happens because the bond between potassium and bromide is ionic.
• The bond is formed by the transfer of an electron from potassium to a bromide ion.
• The ions bonded together by ionic bonds get easily dissociated in water or aqueous solutions.
• The reaction of dissociation of potassium bromide is given as:

        $\[KBr \to {K^ + } + B{r^ - }\]$