Question

Write the equation in standard form of the line that has x-intercept 7 and y-intercept 4

Answer 1

By the intercept form of line,

$\frac{x}{a} +\frac{y}{b} =1$

where a and b are the x and y intercepts respectively

Hence the equation becomes

$\frac{x}{7} +\frac{y}{4} =1\\\\\frac{4x+7y}{28} =1\\\\4x+7y=28$

Therefore the srtandard equation becomes

4x + 7y - 28 = 0

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