Write the equations of any two lines passing through the point (2, - 3).
Answers
Answer: x + y = -1
x^2 + y^2 +2xy = 1
Step-by-step explanation:
x + y = -1
x^2 + y^2 +2xy = 1
these are two lines passing through point (2 , -3 )
hope u like it :-)
Answer:
Let the slope of the other line be m
2
The angle between the two lines is 60
∘
∴tan60
∘
=
∣
∣
∣
∣
∣
1+m
1
m
2
m
1
−m
2
∣
∣
∣
∣
∣
⇒
3
=
∣
∣
∣
∣
∣
1+2m
2
2−m
2
∣
∣
∣
∣
∣
⇒
3
=±{
1+2m
2
2−m
2
}
⇒
3
=
1+2m
2
2−m
2
or
3
=−{
1+2m
2
2−m
2
}
⇒
3
(1+2m
2
)=2−m
2
or
3
(1+2m
2
)=−(2−m
2
)
⇒
3
+2
3
m
2
+m
2
=2or
3
+2
3m
2
−m
2
=−2
⇒m
2
=
(2
3
+1)
2−
3
orm
2
=
2
3
−1
−(2+
3
)
The equation of line passing through point (2,3) and having a slope of
2
3
+1
(2−
3
)
is
(y−3)=
2
3
+1
2−
3
(x−2)
(2
3
+1)y−3(2
3
+1)=(2−
3
)x−2(2−
3
)
(
3
−2)x+(2
3
+1)y=−1+8
3
In this case the equation of the other line is (
3
−2)x+(2
3
+1)y=−1+8
3
similarly for another one.