Write the equations of motion for a particle rotating about a fixed axis?
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Answered by
27
there are three important equations for a particle rotating about a fixed axis.
1.
2.
3.
where
is the initial angular velocity,
is the final angular velocity ,
is the angular acceleration
and
is the angular position of particle after time t.
1.
2.
3.
where
and
Answered by
16
Hey buddy,
● Kinematics of fixed axis rotation -
The laws of rotational motion and translational motion are analogous to each other.
Consider,
θ = initial angular displacement
ω = initial angular velocity
α = angular acceleration
t = time elapsed
θ' = angular displacement at instant t
ω' = angular velocity at instant t
Now, we can write kinematic eqns of rotational motion as-
1. ω' = ω + αt
2. θ'-θ = ωt + 1/2 αt^2
3. ω'^2 = ω^2 + 2α(θ'-θ)
Hope that is helpful...
● Kinematics of fixed axis rotation -
The laws of rotational motion and translational motion are analogous to each other.
Consider,
θ = initial angular displacement
ω = initial angular velocity
α = angular acceleration
t = time elapsed
θ' = angular displacement at instant t
ω' = angular velocity at instant t
Now, we can write kinematic eqns of rotational motion as-
1. ω' = ω + αt
2. θ'-θ = ωt + 1/2 αt^2
3. ω'^2 = ω^2 + 2α(θ'-θ)
Hope that is helpful...
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