Write the expression for magnetic field inside a solenoid and explain the terms
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The magnitude of the current flowing in the solenoid is (I). ... Integrating the term, we will get the magnetic field for the (2L) length of the solenoid, We note that here the value of (x) is varying from −L to +L. Therefore, we get that∫dB = μ0nIa22+L∫−Ldx2[(r - x)2+a2]32.
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