Question

Write the factors of polynomial p(x)=x^2-9

Answer 1

Hey mate!!!

X^2-(3)^2

(x+3)(x-3)------->By identity

The factors are (-3) and 3.

Hope it helps!!☺️

Answer 2

Given polynomial,

$p(x)= {x}^{2}-9$

But, $9= {3}^{2}$

Therefore, putting the value of 9,

we get,

=> $p(x)= {x}^{2}-{3}^{2}$

Now, we know the algebraic identity,

${a}^{2}-{b}^{2}=(a+b)(a-b)$

So,

In the given simplified polynomial,

a = x and b = 3

Putting the respective values, we get

=> $p(x)= {x}^{2}-{3}^{2}=(x+3)(x-3)$

Now, the given polynomial is factorised .

Hence, the factors of the given polynomial are

$\bold{(x+3)}\:and\:\bold{(x-3)}$