write the first 10 terms of AP and a = 4 d = -3
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Answered by
1
Answer:
a=4,d=-3
a2=a+d=4-3=1
a3=a2+d=1-3=-2
a4=a3+d=-2-3=-5
a5=a4+d=-5-3=-8
a6=a5+d=-8-3=-11
a7=a6+d=-11-3=-14
a8=a7+d=-14-3=-17
a9=a8+d=-17-3=-20
a10=a9+d=-20-3=-23
4,1,-2,-5,-8,-11,-14,-17,-20,-23.....
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Answered by
0
Answer:
1 term=4=a
2 term =a+d=4-3=1
3 term=a+2d=4-6=-2
4 term=a+3d=4-9=-5
so the first 10 terms are 4,1,-2,-5,-8,-11,-14,-17,-20,-23
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