Write the first five terms of a geometric sequence in which the sixth term is 64?
Answers
Answer:
The first 5 terms are
2,4,8,16,32
Step-by-step explanation:
Here the 6th term is given as 64
assuming that 2^6 = 64
∴ its understood that the common ratio is 2
Therefore the terms are
2^1 , 2^2 , 2^3 , 2^4 , 2^5
= 2 , 4 , 8 , 16 , 32
Hope It Helps You
Mark Me As Brainliest
The first five terms of Geometric sequence are 2, 4, 8, 16, 32
Given:
The sixth term of a Geometric sequence is 64
To find:
Write the first five terms of a geometric sequence
Solution:
Given 64 th term of the given Geometric sequence
As we know nth term of Geometric sequence = arⁿ⁻¹
Where a = first term and r = common ratio
Then 6th term of given Geometric sequence = ar⁶⁻¹ = ar⁵
From given data, 6th term 64 = ar⁵
⇒ 2⁶ = ar⁵
⇒ 2(2⁵) = ar⁵
From above calculations, we can conclude that
First term a = 2 and common ratio = 2
Then the required 5 terms are
⇒ a, ar, ar², ar³, ar⁴
⇒ 2, 2(2), 2(2²), 2(2³), 2(2⁴)
⇒ 2, 4, 8, 16, 32
The required five terms of Geometric sequence are 2, 4, 8, 16, 32
#SPJ2