Question

write the first four terms of sequence an=n(n-2)/(n+3)​

Answer 1

Answer:

-1/4 , 0 , 1/2 , 8/7

Step-by-step explanation:

an = n(n-2) / (n+3)

if n=1

a1 = 1 (1-2) / (1+3)

= 1(-1) / (4)

= -1/4

if n=2

a2 = 2(2-2) / (2+3)

= 2 (0) / (5)

= 0

if n=3

a3 = 3(3-2) / (3+3)

= 3(1) / (6)

= 3/6

= 1/2

if n=4

a4 = 4(4-2) / (4+3)

= 4(2) / (7)

= 8/7

I hope it will help you..!!

Thank you..!!