Question

write the first six terms of an A.P in which A=3.5,d=1.5​

Answer 1

Answer:

first six terms are 3.5, 5.0,6.5,8.0,9.5,11.0

Answer 2

Answer:

given first term a = 3.5 , common difference d = 1.5

2nd term of an ap = a + d = 3.5 + 1.5 = 5

3rd term of an ap = a + 2d = 3.5 +2(1.5) = 6.5

4th term of an ap = a + 3d = 3.5 + 3(1.5) = 8

5th term of an ap = a + 4d = 3.5 + 4(1.5) = 9.5

6th term of an ap = a + 5d = 3.5 + 5(1.5) = 11

∴ the sequence is 3.5 , 5 , 6.5 , 8 , 9.5 , 11