Question

Write the first term and common difference of arithmetic sequence 3n+2

Answer 1

Answer:

Let,

t(n) = 3n + 2t(n)=3n+2

so,

if we let n = 1

\begin{gathered}t(1) = 3 \times 1 + 2 \\ t(1) = 5\end{gathered}

t(1)=3×1+2

t(1)=5

hence first term is 5.

now;

t = 2

\begin{gathered}t(2) = 3 \times 2 + 2 \\ t(2) = 8\end{gathered}

t(2)=3×2+2

t(2)=8

second term is 8.

so,

common \: differnce = t(2) - t(1)commondiffernce=t(2)−t(1)

hence,

common difference = 8- 5

common difference= 3.

FINAL ANSWER :

\begin{gathered}first \: term = 5 \\ common \: difference = 3\end{gathered}

firstterm=5

commondifference=3

Answer 2

Answer:

1st term=3x1+2=3+2=5

2nd term =3x2+2=6+2=8

common difference =8-5=3

Therefore a=5,d=3

Step-by-step explanation:

I hope it helps