Question

Write the first two terms of the sequence A n= 3n-2/4n+5
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Answer 1

Answer:

For first term, let n = 1

a1 = [3(1) - 2]/(4(1) + 5)

= 1/9

a2 = [3(2)-2]/[4(2)+5]

= 4/13

Answer 2

The first two terms of the sequence are 1/9 and 4/13

Step-by-step explanation:

The given sequence is A (n)= 3n-2/4n+5

For finding first term put n=1,

$\Rightarrow A\left ( 1 \right )=\frac{\left ( 3-2 \right )}{4+5}$

$\Rightarrow A\left ( 1 \right )=\frac{1}{9}$

For finding second term put n=2,

$\Rightarrow A\left ( 2 \right )=\frac{\left ( 3\times 2-2 \right )}{4\times 2+5}$

$\Rightarrow A\left ( 2 \right )=\frac{4}{13}$

The first two terms of the sequence are 1/9 and 4/13