Question

write the following cubes in expand form:3a+4b cube​

Answer 1

Answer:

(A) The given statement is:]

(3a+4b)^3(3a+4b)

3

Using the identity (a+b)^3=a^3+b^3+3a^2b+3ab^2(a+b)

3

=a

3

+b

3

+3a

2

b+3ab

2

, we have

=(3a)^3+(4b)^3+3(3a)^2(4b)+3(3a)(4b)^2(3a)

3

+(4b)

3

+3(3a)

2

(4b)+3(3a)(4b)

2

=27a^3+64b^3+108a^2b+144ab^227a

3

+64b

3

+108a

2

b+144ab

2

Answer 2

Answer:

(3a+4b)^3

= 27a^3+64b^3 + 36(3a+4b)

(a-b)^3 = a^3 - b^3 - 3ab(a-b)

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