Question

write the following cubes in expanded form (x-2/3*Y)3​

Answer 1

Answer:

x^3 - (2/3y)3 - 3x*2/3y( x-2/3y) . = x^3 - 8/27y3 - 2x/y(x-2/3y). if you want to expand further, we get,. x^3 -8/27y^3 - 2x/y(x)