Math, asked by prathamtrivedi80, 5 hours ago

Write the following cubes in expanded form: (x-2/3y)*3​

Answers

Answered by amansharma264
4

EXPLANATION.

⇒ Expand : (x - 2y/3)³.

As we know that,

Formula of :

⇒ (a - b)³ = a³ - 3a²b + 3ab² - b³.

Using this formula in the equation, we get.

⇒ (x - 2y/3)³ = (x)³ - 3(x)²(2y/3) + 3(x)(2y/3)² - (2y/3)³.

⇒ (x - 2y/3)³ = x³ - 2x²y + 3(x)(4y²/9) - (8y³/27).

⇒ (x - 2y/3)³ = x³ - 2x²y + 4y²x/3 - 8y³/27.

Answered by HarshitJaiswal2534
0

Step-by-step explanation:

EXPLANATION.

⇒ Expand : (x - 2y/3)³.

As we know that,

Formula of :

⇒ (a - b)³ = a³ - 3a²b + 3ab² - b³.

Using this formula in the equation, we get.

⇒ (x - 2y/3)³ = (x)³ - 3(x)²(2y/3) + 3(x)(2y/3)² - (2y/3)³.

⇒ (x - 2y/3)³ = x³ - 2x²y + 3(x)(4y²/9) - (8y³/27).

⇒ (x - 2y/3)³ = x³ - 2x²y + 4y²x/3 - 8y³/27.

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