Question

write the following cubes in the
expended form:(3a+4b)3
$(3a + 4b) {?}^{2}$
​

Answer 1

Step-by-step explanation:

(3a+4b)^3

(3a)^3+(4b)^3+3(3a)^2*4b+3*3a(4b)^2

27a^3+64b^3+108a^2b+144ab^2

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Answer 2

\begin{gathered}(3a - 2b) ^{3} \\ \\ = (3a)^{3} - (2b) ^{3} - 3 \times 3a \times \\ 2b(3a - 2b) \\ \\ = 27a ^{3} - 8b ^{3} - 18ab(3a - 2b) \\ \\ = 27a ^{3} - 8b ^{3} - 54a^{2} b + 36ab ^{2} \end{gathered}

(3a−2b)

3

=(3a)

3

−(2b)

3

−3×3a×

2b(3a−2b)

=27a

3

−8b

3

−18ab(3a−2b)

=27a

3

−8b

3

−54a

2

b+36ab

2