Write the following in the product form
i) 2x3y4z2
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Step-by-step explanation:
We solve the given expression (2x+3y+4z)^2
as shown below:
(2x+3y+4z)^2
=(2x)^2+(3y)^2+(4z)^2+(2×2x×3y)+(2×3y×4z)+(2×4z×2x)
∵(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca)
=4x^2+9y^2+16z^2+12xy+24yz+16zx
Hence, (2x+3y+4z)^2
=4x^2+9y^2+16z^+12xy+24yz+16zx.
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