write the four quantum numbers for 3s^1
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n=3(principal)
l=0(azimuthal)
m=l to +l so it is 0(lindie's)
spin=+or 1/2
l=0(azimuthal)
m=l to +l so it is 0(lindie's)
spin=+or 1/2
Answered by
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the four quantum numbers for 3s^1 are
n=3(principal)
l=0(azimuthal)
m=l to +l so it is 0(lindie's)
spin=+or 1/2...
n=3(principal)
l=0(azimuthal)
m=l to +l so it is 0(lindie's)
spin=+or 1/2...
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