Math, asked by haldarjitu0, 4 months ago

Write the generalise from of each of the following number​

Answers

Answered by mohdshahid3742
0

Answer:

The given numbers can be written in generalised form as follows:

(a) 39=(3×10)+(9×1)=(3×101)+(9×100)

(b) 52=(5×10)+(2×1)=(5×101)+(2×100)

(c) 106=(1×100)+(0×10)+(6×1)=(1×102)+(0×101)+(6×100)

(d) 359=(3×100)+(5×10)+(9×1)=(3×102)+(5×101)+(9×100)

(e) 628=(6×100)+(2×10)+(8×1)=(6×102)+(2×101)+(8×100)

(f) 3458=(3×1000)+(4×100)+(5×10)+(8×1)=(3×103)+(4×102)+(5×101)+(8×100)

(g) 9502=(9×1000)+(5×100)+(0×10)+(2×1)=(9×103)+(5×102)+(0×101)+(2×100)

(h) 7000=(7×1000)+(0×100)+(0×10)+(0×1)=(7×103)+(0×102)+(0×101)+(0×100)

Answered by sharmamanasvi007
0

Answer:

The given numbers can be written in generalised form as follows:

(a) 39=(3×10)+(9×1)=(3×101)+(9×100)

(b) 52=(5×10)+(2×1)=(5×101)+(2×100)

(c) 106=(1×100)+(0×10)+(6×1)=(1×102)+(0×101)+(6×100)

(d) 359=(3×100)+(5×10)+(9×1)=(3×102)+(5×101)+(9×100)

(e) 628=(6×100)+(2×10)+(8×1)=(6×102)+(2×101)+(8×100)

(f) 3458=(3×1000)+(4×100)+(5×10)+(8×1)=(3×103)+(4×102)+(5×101)+(8×100)

(g) 9502=(9×1000)+(5×100)+(0×10)+(2×1)=(9×103)+(5×102)+(0×101)+(2×100)

(h) 7000=(7×1000)+(0×100)+(0×10)+(0×1)=(7×103)+(0×102)+(0×101)+(0×100)

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