write the hybridisation and number of unpaired electrons is the complex [ NiCl4]², [Atomic number of Ni=28]
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Electronic Configuration of the Ni = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁸
∴ In the Complex Salt, [NiCl₄]²⁻,
the total number of the valence electrons in the Ni = 2
No. of monovalent atom = 4
Charge = -2
∴ Z = 1/2 ( no. of valence electrons in central atom + no. of monovalent atom + Magnitude of negative charge on whole compound - magnitude of positive charge on whole compound)
⇒ Z = (2 + 4 + 2)/2
∴ Z = 4
Now, Z is the measurement for calculating hybridization. It tells the no. of sigma bond and lone pair in compound.
∴ Hybridization = sp³
Geometry = Tetrahedral.
Bond Angle = 109.5°
Hope it helps.
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