write the IUPAC name.
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Answer:Tetraaquairon(III)-u-dihydroxotetraaquairon(III) sulphate.
Explanation:
The lignds are named after adding -u- to each of them. Here both are OH so its -u-dihydroxo . Both sides of the bridge are written as names of two different complexes but without any gap with the lignd part in between.
The oxidation no. is calculated by taking x for both metal atoms together. Here oxidation no. is (4x0) + x -1 -1 + x +(4x0) - (2x-2) = 0 .
=> 2x-6=0
=> x = +3
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