Question

Write the IUPAC name of the following : (i) ( CH3 )2C=CHCOCH3 (ii) CH3CH(Br)CH2C

Answer 1

A) 4 methyl pent-3-ene-2-one.
B) 2 Bromo butane

Answer 2

IUPAC name of $( CH_3 )_2C=CHCOCH_3$ is 4-methylpent-3-ene-2-one and $CH_3CH(Br)CH_2CH_3$ is 2-bromobutane.

Explanation:

IUPAC name of $( CH_3 )_2C=CHCOCH_3$:

• The given compound contains 5 carbon atoms. Thus the root word is 'Pent'.
• The third carbon has a double bond, thus the nature of bonding is denoted by '3-ene'.
• Numbering must be done in such a way that the functional group gets the least number.
• The functional group present in the structure is 'C=O', which is called a ketone group. As it is attached in the second carbon the name of the compound must be suffixed with "2-one".
• At fourth carbon, methyl group is attached. Thus the primary prefix is 4-methyl.
• For the numbering of the carbon atom and location of the functional group refer to the attachment.
• According to the structure given in the attachment, the IUPAC name of the given compound is identified as 4-methylpent-3-en-2-one.

IUPAC name of $CH_3CH(Br)CH_2CH_3$:

• The given compound contains 4 carbon atoms. Thus the root word is '-But'.
• As all the carbon atoms are attached by a single bond, the nature of bonding is denoted by '-ane'.
• The substituent group present in the structure is 'Br' and it is located in second carbon, the name of the compound must be prefixed with "2-Bromo".
• For the numbering of the carbon atom and location of the functional group refer to the attachment.
• According to the structure given in the attachment, the IUPAC name of the given compound is identified as 2 - Bromobutane.

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