Write the IUPAC names of the following:
(1) CH3COCH (ii) CH3COCH2CH3
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Answer:
(i) As there are 3 carbons present and functional group present is ketone. So the IUPAC name is Propanone.
(ii) As there are 4 carbons present and functional group present is ketone. So the IUPAC name is Butanone.
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Answer:
1. 3 methyl 2 butonone
2.Butane 2 one
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