write the least number of five digits which is completely divisible by 39
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The least 5 digit number is 10000.
Now the number has to be divisible by 39.
So let's divide 10000 by 39.
On division we get,
Quotient = 256
Remainder = 16
So if we add the number (39-16) to 10000 it will be completely divisible by 39.
10000+(39-16)
= 10000+23
= 10023
Therefore, required number is 10023.
★ Abhinav Singh ★
Now the number has to be divisible by 39.
So let's divide 10000 by 39.
On division we get,
Quotient = 256
Remainder = 16
So if we add the number (39-16) to 10000 it will be completely divisible by 39.
10000+(39-16)
= 10000+23
= 10023
Therefore, required number is 10023.
★ Abhinav Singh ★
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0
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