Question

write the linear equation such that each point of it's graph has an ordinate one more than 3 1/2 time it abscissa

Answer 1

SOLUTION

TO DETERMINE

The linear equation such that each point of it's graph has an ordinate one more than 3 (1/2) time it abscissa

EVALUATION

Let the coordinates of the point is (x, y)

Abscissa = x and ordinate = y

So by the given condition

$\displaystyle \sf{y = 3 \frac{1}{2} x + 1}$

$\displaystyle \sf{ \implies \: y = \frac{7}{2} x + 1}$

$\displaystyle \sf{ \implies \: y = \frac{7x}{2} + 1}$

$\displaystyle \sf{ \implies \:2 y = 7x + 2 }$

$\displaystyle \sf{ \implies \:7x - 2y + 2 = 0}$

Which is the required linear equation

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