write the magnitude of components of A in the direction of x and y
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Let the vector is A having magnitude a and making an angle x with x axis.so, the components are
acosx=n+1
asinx=1
When coordinates are rotated by 600, the angle can be x+60orx−60 ,the new coordinates are
acos(x±60)=n
asin(x±60)=3
Now, solving four equations we get
acos(x±60)=a(cosxcos60±sinxsin60)
n=a(
2
1
cosx±
2
3
sinx)
put,acosx=n+1andasinx=1
so,n=1±
3
n depends on direction of rotation.
Explanation:
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