Question

Write the mathematical expression for Joule's law of heating.
Compute the heat generated while transferring 96000 coulomb of
charge in two hours through a potential difference of 40 V.​

Answer 1

Answer:

H=I^2R

or

H=V^2/R

Explanation:

P=VI

thus,    96000=40*I

I=96000/40

=2400A

V=IR

40=2400*R

R=40/2400

=1/60

H=I^2R

=2400*2400*1/60

=2400*40

=96000