Write the MO configuration of O2+1, O2, O2-1. Calculate their bond order. Mention its magnetic behavior.
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Answer:
As it can be seen from the MOT of O
2
, The electrons in the highest occupied molecular orbital are unpaired therefore it is paramagnetic in nature. Also, the bond order can be calculated as [N
b
−N
a
]/2=[10−6]/2=2. Therefore there is a double bond present as O=O.
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