Question

write the molecular formula of oxides of the following elements by referring to the mendeleev s pérodic table
Na-
si-
ca-
ca-
Rb-
Ba-
ci-
sn-
p-



​

Answer 1

Explanation:

1.NA: The element sodium belongs to group I of Mendeleev's periodic table in which the general formula of oxides of elements is R2O. So formula of oxide of Sodium is Na2O.

2) si: The element Silicon belongs to Group IV of Mendeleev's periodic table in which the general formula is RO2. So, the formula for oxide of Si is SiO2. Sn belongs same group so formula of its oxide is SnO2.

3) Ca :belongs to group II of Mendeleev's periodic table. The general formula of Oxide is RO. So formula for Oxide of Ca is CaO. Ba belongs to this group, so formula of oxide is BaO.

The element Silicon belongs to Group IV of Mendeleev's periodic table in which the general formula is RO2. So, the formula for oxide of Si is SiO2. Sn belongs same group so formula of its oxide is SnO2

Answer 2

Correct Question:

Write the molecular formulae of oxides of the following elements by referring to the Mendeleev's periodic table. Na, Si, C, Rb, P, Ba, Cl, Sn, Ca.

Answer:

Molecular formulae of oxides of elements.

Explanation:

$\begin{array}{|c|c|}\cline{1-2}\bf\:Elements & \bf\:Oxides\:of\:elements\\\cline{1-2}\sf\:Na & \sf\:Na_2O\:Sodium\:oxide\\\sf\:Si & \sf\:SiO_2\:Silicon\:dioxide\\\sf\:C & \sf\:CO_2\:Carbon\:dioxide\\\sf\:Rb & \sf\:Rb_2O\:Rubidium\:oxide\\\sf\:P & \sf\:P_2O_5\:Phosphorus\:pentaoxide\\\sf\:Ba & \sf\:BaO\:Barium\:oxide\\\sf\:Cl & \sf\:Cl_2O\:Chloride\:monoxide\\\sf\:Sn & \sf\:SnO_2\:Tin\:oxide\\\sf\:Ca & \sf\:CaO\:Calcium\:oxide\\\cline{1-2}\end{array}$

$\rule{200}{1}$

Additional Information:

1. Oxides of elements:

When an element reacts with oxygen, the product formed is called oxide of element.

2. Oxides of metals are basic in nature.

3. Oxides of non-metlas are acidic in nature.