write the molecular formula of the 2nd and 3rd member of the homologous series. where the first member is ethyne
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Propyne and Methyne is the answer
Sanyamagarg2776:
We have to write molecular formula not name
C3H7-Propyne
C4H9
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The members of homologous series differ by CH2.
If the first member is ethyne i.e C2H2
Then 2nd member will be C3H4 (propyne)
And 3rd member will be C4H6 (butyne).
Hope it helps.
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