Write the molecular formula of the first two members of the homologous series having functional group – COOH.
Answers
Answered by
87
hey friend,
here's your answer,
the 1st two members are:
HCOOH (methanoic acid)
CH3COOH (ethanoic acid)
hope it helps to you.....!
here's your answer,
the 1st two members are:
HCOOH (methanoic acid)
CH3COOH (ethanoic acid)
hope it helps to you.....!
SHOAIBXO:
can i see the steps too
Answered by
22
Molecular formula of the first two members of the homologous series having functional group – COOH.
Explanation:
- The compound which contains '-COOH" as functional group, it is called as carboxylic acid.
- To write the molecular formula of the first two members of the homologous series, the general formula of carboxylic acid must be used.
- The general formula of this compound is .
- To find the first and second members of homologous series, consider n = 0 and 1. Accordingly
The molecular formula of the first member:
n = 0
Molecular formula of first member =
Molecular formula of first member =
Molecular formula of first member = (Methanoic acid)
The molecular formula of the second member:
n = 1
Molecular formula of second member =
Molecular formula of second member =
Molecular formula of second member = (Ethanoic acid)
Learn more about such concept
Write the molecular formula of an alkyne containing 10 atoms of hydrogen.
brainly.in/question/5995474
Name the second member of alkyne series and give its structure
brainly.in/question/2116754
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