Chemistry, asked by Delores5580, 1 year ago

Write the molecular formula of the first two members of the homologous series having functional group – COOH.

Answers

Answered by sgwaeutraav
87
hey friend,
here's your answer,
the 1st two members are:
HCOOH (methanoic acid)
CH3COOH (ethanoic acid)
hope it helps to you.....!

SHOAIBXO: can i see the steps too
Answered by zumba12
22

Molecular formula of the first two members of the homologous series having functional group – COOH.

Explanation:

  • The compound which contains '-COOH" as functional group, it is called as carboxylic acid.
  • To write the molecular formula of the first two members of the homologous series, the general formula of carboxylic acid must be used.
  • The general formula of this compound is C_nH_{2n+1}COOH.
  • To find the first and second members of homologous series, consider n = 0 and 1. Accordingly

The molecular formula of the first member:

n = 0

Molecular formula of first member = C_nH_{2n+1}COOH

Molecular formula of first member = C_0H_{2(0)+1}COOH

Molecular formula of first member = CHCOOH (Methanoic acid)

The molecular formula of the second member:

n = 1

Molecular formula of second member = C_nH_{2n+1}COOH

Molecular formula of second member = C_1H_{2(1)+1}COOH

Molecular formula of second member = CH_{3}COOH (Ethanoic acid)

Learn more about such concept

Write the molecular formula of an alkyne containing 10 atoms of hydrogen.

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