Question

Write the molecular formula of the first two members of the homologous series having functional group – COOH.

Answer 1

hey friend,
here's your answer,
the 1st two members are:
HCOOH (methanoic acid)
CH3COOH (ethanoic acid)
hope it helps to you.....!

Answer 2

Molecular formula of the first two members of the homologous series having functional group – COOH.

Explanation:

• The compound which contains '-COOH" as functional group, it is called as carboxylic acid.
• To write the molecular formula of the first two members of the homologous series, the general formula of carboxylic acid must be used.
• The general formula of this compound is $C_nH_{2n+1}COOH$.
• To find the first and second members of homologous series, consider n = 0 and 1. Accordingly

The molecular formula of the first member:

n = 0

Molecular formula of first member = $C_nH_{2n+1}COOH$

Molecular formula of first member = $C_0H_{2(0)+1}COOH$

Molecular formula of first member = $CHCOOH$ (Methanoic acid)

The molecular formula of the second member:

n = 1

Molecular formula of second member = $C_nH_{2n+1}COOH$

Molecular formula of second member = $C_1H_{2(1)+1}COOH$

Molecular formula of second member = $CH_{3}COOH$ (Ethanoic acid)

Learn more about such concept

Write the molecular formula of an alkyne containing 10 atoms of hydrogen.

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Name the second member of alkyne series and give its structure

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