write the molecular formula of the second and third member of the homologous series whose first member is ethene
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10
As the first member is ethane,
It has the suffix “ane” so this means that the compound is an alkane
The 2nd member of the series will be propane
The general formula for alkane is CnH2n+2CnH2n+2
So the n is the number of Carbon atoms. The number of Carbon atoms in propane is 3
The formula is C3H8C3H8
The 3rd member of the homologous series will have 4 carbon atoms
The name of the compound is butane
The formula is C4H10
It has the suffix “ane” so this means that the compound is an alkane
The 2nd member of the series will be propane
The general formula for alkane is CnH2n+2CnH2n+2
So the n is the number of Carbon atoms. The number of Carbon atoms in propane is 3
The formula is C3H8C3H8
The 3rd member of the homologous series will have 4 carbon atoms
The name of the compound is butane
The formula is C4H10
Answered by
20
As the first member is ethane,
It has the suffix “ane” so this means that the compound is an alkane
The 2nd member of the series will be propane
The general formula for alkane is CnH2n+2CnH2n+2
So the n is the number of Carbon atoms. The number of Carbon atoms in propane is 3
The formula is C3H8C3H8
The 3rd member of the homologous series will have 4 carbon atoms
The name of the compound is butane
The formula is C4H10
It has the suffix “ane” so this means that the compound is an alkane
The 2nd member of the series will be propane
The general formula for alkane is CnH2n+2CnH2n+2
So the n is the number of Carbon atoms. The number of Carbon atoms in propane is 3
The formula is C3H8C3H8
The 3rd member of the homologous series will have 4 carbon atoms
The name of the compound is butane
The formula is C4H10
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