Question

write the molecular orbital electronic configuration for oxygen molecule calculate its bond order and comment on its magnetic property​

Answer 1

Explanation:

Atomic number of oxygen = 8. Electronic configuration of oxygen = 1s22s22p4. When two oxygen atoms combines, the molecular orbital energy level diagram is as shown in the figure. From the diagram, the molecular electronic configuration of oxygen is Magnetic property: There are two unpaired electrons therefore, oxygen molecule is a paramagnetic in nature.Read more on Sarthaks.com - https://www.sarthaks.com/577580/write-electronic-configuration-energy-level-diagram-molecular-orbitals-oxygen-molecule

Answer 2

Explanation:

σ1s2σ∗1s2σ2s2σ∗2s2π2px2=π2py2

σ1s2σ∗1s2σ2s2σ∗2s2π2px2=π2py2bond order =NB−NA2=12(8−4)=2

σ1s2σ∗1s2σ2s2σ∗2s2π2px2=π2py2bond order =NB−NA2=12(8−4)=2Since there are no unpaired electron it is diamagnetic in nature