Question

write the natural of the roots of the quadratic equation 2 x square - 3 x + 1 = 0​

Answer 1

firstly , compare equation with ax²+bx+c

a=2 , b = -3 and C = 1

then after that we know ,

D=b²-4ac

hence , D = (-3)² - 4 × 2 × 1

= 9 - 6

= 3

since , D>0

3 is the real root .

Answer 2

Answer:

$2 {x}^{2} - 3x + 1 = 0 \\ \\ 2 {x}^{2} - 2x - 1x + 1 = 0 \\ \\ x(x - 2) - 1(x - 2) = 0 \\ \\ (x - 2)(x - 1) = 0 \\ x = 1 \\ x = 2$

here is your answer.

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