Math, asked by vinny375, 1 year ago

write the nature of roots of quadratic equation 4x square + 6 X + 3 is equals to zero

Answers

Answered by tanayajagadale
37
EQ : 4X^2 + 6X + 3

a= 4 , b = 6 , c = 3

∆ = b^2 - 4 ac
= 6^2 - 4 (4)(3)
= 36- 16 (3)
= 36 - 48
= -12
∆ = -12

therefore ∆ < 0
the nature of root is not real.


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Answered by prakrithi89
9

Answer:

No real roots

Step-by-step explanation:

b^2-4ac

a = 4, b = 6, c = 3

6^2 - 4×4×3

36 - 48

-12

b^2 - 4ac < 0

there fore No real roots

I hope it will help you

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