write the nature of roots of quadratic equation 4x square + 6 X + 3 is equals to zero
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Answered by
37
EQ : 4X^2 + 6X + 3
a= 4 , b = 6 , c = 3
∆ = b^2 - 4 ac
= 6^2 - 4 (4)(3)
= 36- 16 (3)
= 36 - 48
= -12
∆ = -12
therefore ∆ < 0
the nature of root is not real.
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a= 4 , b = 6 , c = 3
∆ = b^2 - 4 ac
= 6^2 - 4 (4)(3)
= 36- 16 (3)
= 36 - 48
= -12
∆ = -12
therefore ∆ < 0
the nature of root is not real.
I hope this helps u...
plz mark as brainlist...✌️✌️
Answered by
9
Answer:
No real roots
Step-by-step explanation:
b^2-4ac
a = 4, b = 6, c = 3
6^2 - 4×4×3
36 - 48
-12
b^2 - 4ac < 0
there fore No real roots
I hope it will help you
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