Question

write the nature of the graph of the equations 6x -2y +9=0and 3x - y +12=0

Answer 1

Heya... I think this can be ur answer!!!
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6x - 2y + 9 =0
3x - y +12=0
Now,
a1 = 6 a2 = 3
b1 = - 2 b2 = - 1
c1 = 9 c2 =12

SO,
6/3 = - 2/-1 is not equal to 9/12
So,
a1/a2 = b1/b2
So,
The lines are parallel and equations have no solution...

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Hope it helps you dear ☺️☺️

Answer 2

The graph of the lines will be two straight parallel lines.

• To check the nature of the graph we have to check the number of solutions to the given equations.
• The given lines are 6x -2y +9=0and 3x - y +12=0.
• a1=6,a2=3,b1=, -2 and b2=-1
• To check the number of solutions, we have to compare a1/a2. and b1/b2.,
• So, 6/3=2 is equal to -2/-1=2.
• In this case, the system of equations will have infinitely many solutions. It means that the lines are parallel to each other. Such will be the graph.

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