Question

write the nature of the root without solving the equation 2 x square minus 3 root 2 X + 9/4 =0​

Answer 1

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$\sf \: 2 {x}^{2} - 3 \sqrt{2x} + \frac{9}{4} = 0$

$\sf \: a = 2 \: , \: b = 3 \sqrt{2} \: , \: c = \frac{9}{4}$

Discrimant D= b²-4ac=48-48=0

Since D=0, the roots are real and equal for the given equation.

$\sf \: 2 {x}^{2} - 3 \sqrt{2x} + \frac{9}{4} = 0$

$\large \sf \: x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac} }{2a}$

$\large \sf \: x = \frac{3 \sqrt{2} }{4} = \frac{2}{ \sqrt{3} }$

Hope it helps you.....

Answer 2

Answer:

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