Question

write the nature of the roots of the quadratic equation 2xsquare-3x+1equals to 0​

Answer 1

2x^2 - 3x + 1 = 0

Here,

a= 2

b= -3

c= 1

Discrimination (D)

= b^2 - 4ac

= (-3)^2 - 4 × 2 × 1

= 9 - 8

= 1

As, D > 0, the nature of the roots of the quadratic equation are real and distinct.

Answer 2

Hey manya here is your answer....

$2 {x}^{2} - 3x + 1$

a = 2 , b = -3 , c = 1

$= {b}^{2} - 4ac$

$= ({3})^{2} - 4 \times 2 \times 1$

= 9 - 8

= 1

# Discriminate is greater than 0

# Nature of the roots is real and unequal.

Hope it helps you.

Thank you.