Question

write the next term of the AP under root 2, under root 8, 18​

Answer 1

Answer:

Step-by-step explanation:

Root 2 and root 8 =2root 2

A=root 2

Second term 2root2

3rd term 3 root 2... And so on 4root2, 5root2

Answer 2

Answer:

A.P.:-

$\sqrt{2} , \sqrt{8} , \sqrt{18}$

d (common difference) =$\sqrt{8} - \sqrt{2} = 2\sqrt{2} - \sqrt{2}\\\sqrt{2}( 2 - 1) = \sqrt{2}$

So $\sqrt{18} +\sqrt{2} = 3\sqrt{2} + \sqrt{2}$

$\sqrt{2}(3+1) = 4\sqrt{2} = \sqrt{4x4x2} =\sqrt{32}$