Question

write the no of zeroes in the end of a no whose prime factorisation is 2^2*5^3*3^2*17​

Answer 1

Step-by-step explanation:

Here, the number 76,500 is having two zeros at its end. So, the number 2² * 5³ * 3² * 17 have two zeros at its ending. Thus, the number 2² * 3² * 5³ * 17 has 2 zeros at its ending.

Answer 2

Step-by-step explanation:

Given prime factorization is

2^2*5^3*3^2*17

=>4×125×9×17

=>500×153

=>76500

It has two zeroes in the end of the given

prime factorization.